If log b 3=0.5
log b 5= 0.7
evaluate log b √3
√6
Log b √3=logb 3^1/2
=1/2 logb 3
1/2(0.5)
=.25
Am I on the right track? And if I am, the √6 is somewhat throwing me off. Can I get help with that please? Ty
Now, I am confused in what you wrote, lol.
So logb √3 equals to logb(3)/2?
Let me try to re-write this problem. No clue what this LaTeX thing is, so please forgive me.
If log b 3=0.5
logb 5= 0.7
Now I have to evaluate log √3 and log √6. My steps for √3 is already posted above this for that problem.
If, by "log b" you mean "log base b", $\displaystyle log_b$ or log_b then
Use the laws of logarithms: $\displaystyle log_b(\sqrt{3})= log_b(3^{1/2})= (1/2)log_b(3)$ exactly as you say.
$\displaystyle log_b(\sqrt{6})= log_b(6^{1/2})= (1/2)log_b(6)= (1/2)log_b(2(3))$$\displaystyle = (1/2)(log_b(2)+ log_b(3))$.