Thread: Dazed and Confused

If log b 3=0.5
log b 5= 0.7

evaluate log b √3
√6


Log b √3=logb 3^1/2

=1/2 logb 3

1/2(0.5)
=.25

Am I on the right track? And if I am, the √6 is somewhat throwing me off. Can I get help with that please? Ty

Originally Posted by Past45

If log b 3=0.5
log b 5= 0.7

evaluate log b √3
√6


Log b √3=logb 3^1/2

=1/2 logb 3

1/2(0.5)
=.25

Am I on the right track? And if I am, the √6 is somewhat throwing me off. Can I get help with that please? Ty

It is almost impossible to read what you posted.
Learn to use basic LaTeX.
[TEX]\log_b\sqrt{3}=\frac{\log_b(3)}{2}[/TEX] gives .

Now, I am confused in what you wrote, lol.

So logb √3 equals to logb(3)/2?


Let me try to re-write this problem. No clue what this LaTeX thing is, so please forgive me.

If log b 3=0.5
logb 5= 0.7


Now I have to evaluate log √3 and log √6. My steps for √3 is already posted above this for that problem.

If, by "log b" you mean "log base b", or log_b then

Use the laws of logarithms: exactly as you say.

.