Solve equation (link provided)

**HellBunny** · April 18th 2012, 05:43 PM

http://i43.tinypic.com/34rhbpl.png
I've tried to solve it, but here's my answer, not sure if it's right. . .[-infinite,1) U (4, infinite )..

**skeeter** · April 18th 2012, 06:04 PM

$\frac{x+1}{x-4} \ge 0$

see the video ...

**HellBunny** · April 18th 2012, 06:32 PM

The answer is (-infinite, -1) U [4, infinite) ?

**skeeter** · April 19th 2012, 03:05 AM

Originally Posted by HellBunny

The answer is (-infinite, -1) U [4, infinite) ?

almost ...

$(-\infty,-1] \cup (4,\infty)$

**HellBunny** · April 26th 2012, 05:27 AM

Plugged 2, 5, and 8. 2=False, 5 = True, 8 = False.
Answer:

Code:

[3,7)

correct?

**biffboy** · April 26th 2012, 05:46 AM

Correct interval but have to indicate that 3 is included but not 7

**HellBunny** · April 26th 2012, 07:39 AM

Ah, thanks.

Hey, another question.. how do I solve this? $125^{2}{3}$ the 2/3 is an exponent.

**Prove It** · April 26th 2012, 08:24 AM

Originally Posted by HellBunny

Ah, thanks.

Hey, another question.. how do I solve this? $125^{2}{3}$ the 2/3 is an exponent.

$\displaystyle \begin{align*} 125^{\frac{2}{3}} &= \left(125^{\frac{1}{3}}\right)^2 \\ &= \left(\sqrt[3]{125}\right)^2 \\ &= 5^2 \\ &= 25 \end{align*}$

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