Solve equation (link provided)

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April 18th 2012, 05:43 PM
HellBunny

Solve equation (link provided)

http://i43.tinypic.com/34rhbpl.png
I've tried to solve it, but here's my answer, not sure if it's right. . .[-infinite,1) U (4, infinite )..
April 18th 2012, 06:04 PM
skeeter

Re: Solve equation (link provided)

$\frac{x+1}{x-4} \ge 0$

see the video ...

http://youtu.be/SJecFvUbJOY
April 18th 2012, 06:32 PM
HellBunny

Re: Solve equation (link provided)

The answer is (-infinite, -1) U [4, infinite) ?
April 19th 2012, 03:05 AM
skeeter

Re: Solve equation (link provided)

Quote:

Originally Posted by HellBunny

The answer is (-infinite, -1) U [4, infinite) ?

almost ...

$(-\infty,-1] \cup (4,\infty)$
April 26th 2012, 05:27 AM
HellBunny

Re: Solve equation (link provided)

http://i49.tinypic.com/2v3of9f.jpg
Plugged 2, 5, and 8. 2=False, 5 = True, 8 = False.
Answer:

Code:

[3,7)

correct?
April 26th 2012, 05:46 AM
biffboy

Re: Solve equation (link provided)

Correct interval but have to indicate that 3 is included but not 7
April 26th 2012, 07:39 AM
HellBunny

Re: Solve equation (link provided)

Ah, thanks. :D Hey, another question.. how do I solve this? $125^{2}{3}$ the 2/3 is an exponent.
April 26th 2012, 08:24 AM
Prove It

Re: Solve equation (link provided)

Quote:

Originally Posted by HellBunny

Ah, thanks. :D Hey, another question.. how do I solve this? $125^{2}{3}$ the 2/3 is an exponent.

$\displaystyle \begin{align*} 125^{\frac{2}{3}} &= \left(125^{\frac{1}{3}}\right)^2 \\ &= \left(\sqrt[3]{125}\right)^2 \\ &= 5^2 \\ &= 25 \end{align*}$

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