• April 18th 2012, 05:43 PM
HellBunny
http://i43.tinypic.com/34rhbpl.png
I've tried to solve it, but here's my answer, not sure if it's right. . .[-infinite,1) U (4, infinite )..
• April 18th 2012, 06:04 PM
skeeter
$\frac{x+1}{x-4} \ge 0$

see the video ...

http://youtu.be/SJecFvUbJOY
• April 18th 2012, 06:32 PM
HellBunny
The answer is (-infinite, -1) U [4, infinite) ?
• April 19th 2012, 03:05 AM
skeeter
Quote:

Originally Posted by HellBunny
The answer is (-infinite, -1) U [4, infinite) ?

almost ...

$(-\infty,-1] \cup (4,\infty)$
• April 26th 2012, 05:27 AM
HellBunny
http://i49.tinypic.com/2v3of9f.jpg
Plugged 2, 5, and 8. 2=False, 5 = True, 8 = False.
Code:

[3,7)
correct?
• April 26th 2012, 05:46 AM
biffboy
Correct interval but have to indicate that 3 is included but not 7
• April 26th 2012, 07:39 AM
HellBunny
Ah, thanks. :D Hey, another question.. how do I solve this? $125^{2}{3}$ the 2/3 is an exponent.
Ah, thanks. :D Hey, another question.. how do I solve this? $125^{2}{3}$ the 2/3 is an exponent.
\displaystyle \begin{align*} 125^{\frac{2}{3}} &= \left(125^{\frac{1}{3}}\right)^2 \\ &= \left(\sqrt[3]{125}\right)^2 \\ &= 5^2 \\ &= 25 \end{align*}