How would I solve this problem? (16x^5+2x^4+x^3) / 4x
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Originally Posted by Capnzims How would I solve this problem? (16x^5+2x^4+x^3) / 4x $\displaystyle \frac{16x^5}{4x} + \frac{2x^4}{4x} + \frac{x^3}{4x}$ finish by dividing each term ...
so the answer is 4x^4+1/2x^3+x^2? Sorry to not understand. How would I do this long division style?
I get it now sorry for being stupid. Another question please with this one. 4x^3(2x^4+8x^3+12x^3) I get x/2+2+3/x but my book says the answer is x/2+2(3/x) is it the same thing or?
Originally Posted by Capnzims I get it now sorry for being stupid. Another question please with this one. 4x^3(2x^4+8x^3+12x^3) I get x/2+2+3/x but my book says the answer is x/2+2(3/x) is it the same thing or? is this a division problem? looks like multiplication to me.
no that was a division problem.. this (2x^4+8x^3+12x^3) divided by 4x^3.
Originally Posted by Capnzims no that was a division problem.. this (2x^4+8x^3+12x^3) divided by 4x^3. note that $\displaystyle 2x^4+8x^3+12x^3 = 2x^4 + 20x^3$ $\displaystyle \frac{2x^4 + 20x^3}{4x^3} = \frac{x}{2} + 5$ sure you copied it correctly?
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