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Math Help - (1000/205-x)-(1000/205+x)=1

  1. #1
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    (1000/205-x)-(1000/205+x)=1

    Hello, you guys can call me Azusa.; I am new to this forum. Sorry to introduce myself in such an impolite way, but I have a test at 8am later (and yes I'm pulling an all-nighter to review everything). I've focused on one area of the chapters so much that I have no idea how to do the other problems.

    I appreciate any help!!

    Thank You,
    Azusa.

    (One of the problems on the Quadratic Equations chapter).
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  2. #2
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    Re: (1000/205-x)-(1000/205+x)=1

    Multiply each term (both sides) by (205-x)(205+x) Get 1000(205+x)-1000(205-x)=(205-x)(205+x)

    So 205000+1000x-205000+1000x= 42025-x^2 So x^2+2000x-42025=0 Formula gives x= 20.8 or -2020.8
    Thanks from Azusa
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  3. #3
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    Re: (1000/205-x)-(1000/205+x)=1

    Ok, I got to x+2000x-42025=0
    but I don't quite get how you got x=20.8 or -2020.8

    After getting x+2000x-42025=0, I used the Quadratic Forumla; (-b√b-4ac)/2a
    Ended up with this: x=(-2000√3831900)/2
    Then √3831900 (calculator): 1957.523946, thus, x=(-20001957.523946)/2

    I don't get how to do that last step.. Am I supposed to add/substract -2000 and 1957.523946 then divide by 2? but that doesn't seem to get me the answer..

    Thank You,
    Azusa.
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  4. #4
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    Re: (1000/205-x)-(1000/205+x)=1

    Your number under the square root sign is wrong. We have a=1 b=2000 and c=-42025


    So b^2-4ac= (2000)^2-4(1)(-42025) =4000000+168100=4168100
    Thanks from Azusa
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  5. #5
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    Re: (1000/205-x)-(1000/205+x)=1

    Wow. x.x What a dumb mistake. I just wasted 3 hours being stupid. :c
    Anyway, I APPRECIATE your help. Couldn't thank you enough.

    TYVM,
    Azusa.
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