Multiply each term (both sides) by (205-x)(205+x) Get 1000(205+x)-1000(205-x)=(205-x)(205+x)
So 205000+1000x-205000+1000x= 42025-x^2 So x^2+2000x-42025=0 Formula gives x= 20.8 or -2020.8
Hello, you guys can call me Azusa.; I am new to this forum. Sorry to introduce myself in such an impolite way, but I have a test at 8am later (and yes I'm pulling an all-nighter to review everything). I've focused on one area of the chapters so much that I have no idea how to do the other problems.
I appreciate any help!!
(One of the problems on the Quadratic Equations chapter).
Ok, I got to x²+2000x-42025=0
but I don't quite get how you got x=20.8 or -2020.8
After getting x²+2000x-42025=0, I used the Quadratic Forumla; (-b±√b²-4ac)/2a
Ended up with this: x=(-2000±√3831900)/2
Then √3831900 (calculator): 1957.523946, thus, x=(-2000±1957.523946)/2
I don't get how to do that last step.. Am I supposed to add/substract -2000 and 1957.523946 then divide by 2? but that doesn't seem to get me the answer..