log6(x+1) + log6(x+2) = 1

The 6 in both equations is the base.

I know that...

log6(x+1) + log6(x+2) = log6(x+1)(x+2)

So I get to here.

log6(x+1)(x+2) = 1

I assume we have to make it equal to 0.

log6(x^2+3x+2) = 1

log6(x^2+3x+1) = 0

Tell me if I'm doing something wrong here.

The answer is supposed to be 1, but I don't understand how to get to the answer.