log6(x+1) + log6(x+2) = 1
The 6 in both equations is the base.
I know that...
log6(x+1) + log6(x+2) = log6(x+1)(x+2)
So I get to here.
log6(x+1)(x+2) = 1
I assume we have to make it equal to 0.
log6(x^2+3x+2) = 1
log6(x^2+3x+1) = 0
Tell me if I'm doing something wrong here.
The answer is supposed to be 1, but I don't understand how to get to the answer.