The question is to prove the "k" in the following queston is equal to: k = 1/10Loge(10/7)
and the original question is 70 = 100e-k10
I'll show the steps i have used so far, but i don't understand the next step needed..
> 70/100 = e-k10
> 7/10 = e-k10
> loge(7/10) = -k10
That is as far as i can get, if you know the next step please respond with the Log law that goes with it, Any help would be appreciated.