thank you I got it!
I feel dumb asking some of these because they look so basic but I want to make sure I know what I'm doing.
1. The domain and range of 5x cubed + 4
I got negative infinite - positive infinite.
2. Write as exponential form: ln 1 = 0
I got 10^0 = 1
3. Use properties of logarithms to rewrite the expression: 4 log base 2 a squared
I got log base 2 a^8
4. Solve the equation: log x = -2
I got 10^-2 = .01
X = .01
5. 2 ln y = 9
I got 2y = ln 9
2y = 2.1972
y = 1.0986
You mean both domain and range are negative to positive infinity (or "all real numbers"). Yes, that is correct.
Yes.2. Write as exponential form: ln 1 = 0
I got 10^0 = 1
Yes, that is correct. "8 log base 2 a" would also be a correct answer.3. Use properties of logarithms to rewrite the expression: 4 log base 2 a squared
I got log base 2 a^8
Yes, assuming that the logarithm is base 10. In advanced mathematics log base 10 is used so seldom that "log" is often used to mean natural logarithm but since you use "ln" in the next problem, you are probably correct that "log" is base 10.4. Solve the equation: log x = -2
I got 10^-2 = .01
X = .01
No, no , no , no!!! You can't just "take" a ln from one side and put it on the other!5. 2 ln y = 9
I got 2y = ln 9
2y = 2.1972
First step- either use the properties of logarithms to write [itex]2 ln y= ln y^2= ln 9[/itex] or divide both sides by 2 to get $\displaystyle ln(y)= (1/2)ln(9)= ln(9^{1/2})= ln(3)$.
Then use the fact that ln is "one to one": if ln a= ln b then a= b.
y = 1.0986