Partial fractions - I have trouble solving this one

Hi,

I have managed to successfully answer all of the other partial fractions questions in my textbook but can't see how the following one is done:

http://i73.photobucket.com/albums/i210/shingo3/Q1.png

The denominator is factorised to:

http://i73.photobucket.com/albums/i210/shingo3/Q2.png

And then the textbook has been giving the following method to allow solving for A and B as the numerators:

http://i73.photobucket.com/albums/i210/shingo3/Q3.png

I am having trouble knowing what to make x to cancel out the A part and thus solve for B. To make A = 0 wouldn't x have to = 0.333...

This is the answer given in the back of the book:

http://i73.photobucket.com/albums/i210/shingo3/Q4.png

Anyway, like I said, I have been OK with the other 10 or so examples but this one has thrown me off and I have spent a long time thinking about it hopefully I have just overlooked something simple.

Any help is much appreciated.

Re: Partial fractions - I have trouble solving this one

It is an identity so true for all values of x. Put x=1/3. This will find you B. Then put in any other x (say x=0) to get A.

Re: Partial fractions - I have trouble solving this one

Thanks for you quick reply, it was really bugging me.

I have got it now, but I was genuinely stuck for long enough before that I signed up here, made those images in LaTeX etc.