# System of two generic equations

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• Apr 7th 2012, 02:27 PM
bmoon123
System of two generic equations
Hi,
I am working on this problem

Consider the following system of linear equations in x and y.

ax + by = e

cx + dy = f

Under what conditions will the system have exactly one solution?

I can come up with specific examples of when this happens but not a generic one just using the variables involved.
• Apr 7th 2012, 03:00 PM
Sylvia104
Re: System of two generic equations
The condition is $\displaystyle ad-bc\ne0.$

Suppose $\displaystyle ad-bc\ne0.$ Then $\displaystyle x=\frac{de-bf}{ad-bc},y=\frac{af-ce}{ad-bc}$ is a solution. If $\displaystyle x=x',y=y'$ is another solution, let $\displaystyle X=\frac{de-bf}{ad-bc}-x',Y=\frac{af-ce}{ad-bc}-y'.$ This gives $\displaystyle aX+bY=0=cX+dY,$ which yields $\displaystyle X=0=Y,$ showing that the solution is unique.

Now suppose $\displaystyle ad-bc=0.$ We have $\displaystyle 0=(ad-bc)x=de-bf$ and $\displaystyle 0=(ad-bc)y=ce-af.$ Then either (1) $\displaystyle de=bf$ and $\displaystyle ce=af,$ in which case $\displaystyle x$ and $\displaystyle y$ can take any arbitrary values and so there are infinitely many solutions, or (2) $\displaystyle de\ne bf$ or $\displaystyle ce\ne af,$ in which case there is no solution in $\displaystyle x$ and $\displaystyle y.$

Hence the system has exactly one solution if and only if $\displaystyle ad-bc\ne0.$
• Apr 7th 2012, 03:14 PM
bmoon123
Re: System of two generic equations
I solved for x and y but didn't know of or think of the test for a second solution by creating the x' and y'. This is fantastically simple. I appreciate the help immensely.

Also, unless I'm mistaken I think your last statement meant to say ad - bc not equal to 0, correct?
• Apr 7th 2012, 03:52 PM
Sylvia104
Re: System of two generic equations
Quote:

Originally Posted by bmoon123
Also, unless I'm mistaken I think your last statement meant to say ad - bc not equal to 0, correct?

Yes. Mistake corrected. (Blush)
• Apr 7th 2012, 09:34 PM
biffboy
Re: System of two generic equations
They are the equations of straight lines. Straight lines intersect at one point only unless they are parallel. So exactly one solution unless gradients equal, that is unless -b/a=-d/c, that is unless ad-bc=0
• Apr 8th 2012, 07:18 AM
bmoon123
Re: System of two generic equations
Quote:

Originally Posted by biffboy
They are the equations of straight lines. Straight lines intersect at one point only unless they are parallel. So exactly one solution unless gradients equal, that is unless -b/a=-d/c, that is unless ad-bc=0

thanks, that makes sense. I think I tend to over think problems like this.

My final answer:

rewritten

y = -(a/b)x + (e/b)

y = -(c/d)x + (f/d)

if a/b = c/d then the slopes of the lines are the same and they are parallel or coincident

so a/b is not equal c/d is the condition needed for exactly one solution
• Apr 8th 2012, 07:54 AM
biffboy
Re: System of two generic equations
That's correct. We would usually finish it off by doing one extra step to say we require ad-bc not to be zero.