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Math Help - intercepts

  1. #1
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    Ardkeen
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    intercepts

    Let f(x) = x4 - 8x2 , where x is a real number.

    Anyone?
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  2. #2
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    Re: Find the co-ordinates of the points where the graph of f(x) cuts the x-axis

    Factorise x^4 - 8x^2=0
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  3. #3
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    Re: Find the co-ordinates of the points where the graph of f(x) cuts the x-axis

    Thanks. I knew it was simple, I just wanted to make sure :P
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  4. #4
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    Re: intercepts

    The graph of f(x) will intersect the x axis at y = 0. So 0 = x^4 - 8x^2 = x^2(x^2-8).

    This gives you x = 0, x = (8)^(1/2) and x = -(8)^(1/2).
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