Let f(x) = x^{4} - 8x^{2 }, where x is a real number. Anyone?
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Factorise x^4 - 8x^2=0
Thanks. I knew it was simple, I just wanted to make sure :P
The graph of f(x) will intersect the x axis at y = 0. So 0 = x^4 - 8x^2 = x^2(x^2-8). This gives you x = 0, x = (8)^(1/2) and x = -(8)^(1/2).
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