2x^2-7X>15

Let me just break it down till the end.

(x-5)(2x+3)>0

x-5-0 2x+3=0

x=5 x=-3/2

When I do my test point and let it be 0 It looks something like

<--//////-----------------------------------------------------///////--------->

True -3 over 2 the middle is F and 5 is also true and the interval notation is (-∞.-3/2)U(5,∞).

My question is, how can -3/2 be greater than 0?