how about -6< x<-1
_{}Ok what am I missing here?
x2 + 7x + 6 > 0 I have this, to solve I factor,
(x+1)(x+6)>0 then
x+1>0 Solve for zero
-1 -1
x>-1 Answer 1
(-1,Infinity) Interval Notation.
Here's where im confused....then
x+6>0
-6 -6
x>-6? right? Answer 2. What am I forgetting cause apparently this is wrong and the
(-6,Infinity) is wrong?
How is this true answer for interval notation (-Infinity, -6) U (-1,Infinity)?
If x>-6, All answers should be going right on number line left.
.
This will be larger than 0 if: (x + 1) and (x+6) are both > 0,
or (x+1) and (x+6) are both < 0.
x+1 > 0 when x > -1. x+6 > 0 when x > -6. So as long as x > -1, (x+1)(x+6) > 0.
x + 1 < 0 when x < -1. x + 6 < 0 when x < -6. So (x+1)(x+6) > 0 as long as x < -6.
Hello, sage1987!
Ok, what am I missing here?
I have this to solve: .
I factor: .
We have: .
. . The product of two numbers is positive.
There are two ways that this can happen.
(1) Both factors are positive: .
(2) Both factors are negative: .
Therefore: .