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Math Help - Quadratic to Standard form

  1. #1
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    Quadratic to Standard form

    I seem to be okay with converting standard form to quadratic, but i am having trouble with the other way around...could someone please help explain it to me?

    How do i convert this to standard form?
    From what i understand, it would be:
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  2. #2
    MHF Contributor
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    You were doing okay until the last line, where you forgot 6*4 = 24

    In the line before the last, you should have removed the 4 from y/4.

    So your initial equation is
    y = 4x^2 -24x +12

    Then,
    y = 4[x^2 -6x +3]
    This has to be done so that the coefficient of the x^2 is 1 only, because completing squares is done when the coefficient of the squared variable is 1 only.

    Then, following your style,
    y = 4[x^2 -6x +9 +3 -9]
    y = 4[(x-3)^2 -6]
    y = 4(x-3)^2 -24
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  3. #3
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    Thank you very much
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