Wolfram didn't give an exact answer, so I doubt there is one...

sum 1/(Sqrt[2n] + Sqrt[2*(n+1)] ) with n from 0 to 1003 - Wolfram|Alpha

Results 1 to 8 of 8

- April 1st 2012, 03:10 AM #1

- Joined
- Sep 2011
- Posts
- 149

- April 1st 2012, 03:17 AM #2
## Re: The value of x

Wolfram didn't give an exact answer, so I doubt there is one...

sum 1/(Sqrt[2n] + Sqrt[2*(n+1)] ) with n from 0 to 1003 - Wolfram|Alpha

- April 1st 2012, 03:24 AM #3

- Joined
- Nov 2011
- From
- Crna Gora
- Posts
- 420
- Thanks
- 64

- April 1st 2012, 03:37 AM #4

- Joined
- Sep 2011
- Posts
- 149

- April 1st 2012, 07:01 AM #5

- Joined
- Dec 2007
- From
- Ottawa, Canada
- Posts
- 3,184
- Thanks
- 80

- April 1st 2012, 08:22 PM #6

- Joined
- Nov 2010
- Posts
- 21

- April 2nd 2012, 08:16 AM #7

- Joined
- Dec 2007
- From
- Ottawa, Canada
- Posts
- 3,184
- Thanks
- 80

- April 9th 2012, 06:43 PM #8

- Joined
- Nov 2010
- Posts
- 21