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Math Help - Solving by Quadratic Formula

  1. #1
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    Solving by Quadratic Formula

    I know the formula but I this problem seems to be wrong when I solve it.

    m^2+5m-6=0

    a=m
    b=5
    c=-6

    x=-5+-√5^2-4(M)(-6) over 2(M)

    So I get -5+-√25-24/2

    -5+-√1/2
    -5+1/2=-2 or -5-1/2=-3

    That is what I got however the answer is suppose to be -6 and 1... Just wondering where I went wrong.
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  2. #2
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    Re: Solving by Quadratic Formula

    Quote Originally Posted by Past45 View Post
    I know the formula but I this problem seems to be wrong when I solve it.

    m^2+5m-6=0

    a=m
    b=5
    c=-6

    x=-5+-√5^2-4(M)(-6) over 2(M)

    So I get -5+-√25-24/2

    -5+-√1/2
    -5+1/2=-2 or -5-1/2=-3

    That is what I got however the answer is suppose to be -6 and 1... Just wondering where I went wrong.
    a is the number that the square term is multiplied by. In this case, a = 1, not m.
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  3. #3
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    Re: Solving by Quadratic Formula

    Right, but it it still is going to have those same numbers when you solve them.
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  4. #4
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    Re: Solving by Quadratic Formula

    m^2+5m-6=0

    m = \frac{-5 \pm \sqrt{5^2 - 4(1)(-6)}}{2}

    try again ... pay close attention to your signs
    Thanks from Past45
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  5. #5
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    Re: Solving by Quadratic Formula

    Got it! Thanks.
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