If I understand correctly, the formula is:

$\displaystyle -\frac{b}{2a}, \frac{4ac-b^2}{4a}$

Here's what I have:

$\displaystyle 33x^2 -2x +15$

First:

$\displaystyle -\frac{2}{2(33)}$ = $\displaystyle \frac{1}{33}$

Easy enough. Now though...

$\displaystyle \frac{4(33)(15)}\frac{4(33)}$

Doing it that way comes up with wildly incorrect answers. I'd type it out but it's just all wrong. The answer in the book is...

$\displaystyle \frac{494}{33}$

However, doing...

$\displaystyle 15-\frac{-2^2}{4(33)}$ does get me

$\displaystyle \frac{494}{33}$

So that's really $\displaystyle C-\frac{(-b)^2}{4(a)}$

So my question is: Why? I'm missing something in the translation and I'm hoping to get some kind of answer. Thanks for any and all help.