this is part of a test, so if you could tell me "how" to do this that would be great!
(x/5)-(x+3/3)=(1/15)
like I said in the title, this is a fractional equation, I keep getting x=7 but it will not come out right when I check it.
any thoughts???
this is part of a test, so if you could tell me "how" to do this that would be great!
(x/5)-(x+3/3)=(1/15)
like I said in the title, this is a fractional equation, I keep getting x=7 but it will not come out right when I check it.
any thoughts???
yes emakarov, sorry about the error. you could say it as "x plus three over three" and I went that route, I will post all of my work and see if you know where my flaw is.
x/5 - (x+3)/3 = 1/15
15(x/5) - 15([x+3]/3) = 15(1/15)
15x/5 - (15x+45)/3 = 1
3x - (5x+15) = 1
(-2x) + 15 = 1
15 = 2x + 1
14 = 2x
7 = x
That looks more confusing on paper... lol but that is what I keep coming to (that 7 = x) and when I use 7 = x and check it I end up with 29/15 = 1/15 (which is quite obviously wrong... LOL)