# fraction equation

• Mar 30th 2012, 01:14 PM
Drummerman
fraction equation
this is part of a test, so if you could tell me "how" to do this that would be great!

(x/5)-(x+3/3)=(1/15)

like I said in the title, this is a fractional equation, I keep getting x=7 but it will not come out right when I check it.
any thoughts???
• Mar 30th 2012, 01:33 PM
emakarov
Re: fraction equation
First, I assume the equation is x/5 - (x + 3)/3 = 1/15 (note the parentheses around x + 3; otherwise x + 3/3 = x + (3/3) = x + 1).

Multiply both sides by 15. Post the result and if you still have a difficulty, describe it.
• Mar 30th 2012, 09:26 PM
Drummerman
Re: fraction equation
yes emakarov, sorry about the error. you could say it as "x plus three over three" and I went that route, I will post all of my work and see if you know where my flaw is.

x/5 - (x+3)/3 = 1/15
15(x/5) - 15([x+3]/3) = 15(1/15)
15x/5 - (15x+45)/3 = 1
3x - (5x+15) = 1
(-2x) + 15 = 1
15 = 2x + 1
14 = 2x
7 = x

That looks more confusing on paper... lol but that is what I keep coming to (that 7 = x) and when I use 7 = x and check it I end up with 29/15 = 1/15 (which is quite obviously wrong... LOL)
• Mar 30th 2012, 10:15 PM
biffboy
Re: fraction equation
Your 5th line should be -2x-15=1
• Mar 31st 2012, 07:58 AM
Drummerman
Re: fraction equation
OH!!! thank you! I guess I pulled down the + instead... I got it now!!!