Re: Linear Transformations

You have a sign wrong in first line of your attempt x'=2x-y gives 2x=x'+y

Re: Linear Transformations

Quote:

Originally Posted by

**GrigOrig99** The question statement says find f(L), which I have highlighted in bold. However, the book's answer seems to continue on and calcualte for y from the f(L) equation

I don't know what you mean by this. From the equation of the line, x- y+ 1= 0, y= x+ 1 so the set is {(x, x+1)}. Applying L to that we have x'= 2x- y= 2x- (x+ 1)= x- 1 and y'= y= x+ 1 so that (x, x+1) is mapped to (x- 1, x+ 1). If x'= x- 1 then x= x'+ 1 and x+ 1= x'+ 2, so we can also write this set as {(x', x'+ 2)}.

Re: Linear Transformations

I just noticed that in the first line it said x'=2x-y => 2x=x'-y. I'm obviously not sure what f(L) means (?). I thought they were asking for the equation which the book gives.

Re: Linear Transformations

Thanks for the help. I'll give it a 2nd look.