# Factor

• Mar 29th 2012, 08:26 AM
Mhmh96
Factor
• Mar 29th 2012, 08:54 AM
princeps
Re: Factor
Quote:

Originally Posted by Mhmh96

1#

$\displaystyle (x+3y)(x+2y+1)$

2#

$\displaystyle \frac{(x+ay)(y+ax)}{a}$
• Mar 29th 2012, 08:59 AM
Mhmh96
Re: Factor
Can you show the steps that lead you to this answer? so i can trace what you did
• Mar 29th 2012, 12:31 PM
Soroban
Re: Factor
Hello, Mhmh96!

Quote:

$\displaystyle \text{Factor: }\;x^2 + x + 6y^2 + 3y + 5xy$

We have: .$\displaystyle (x^2 + 5xy + 6y^2) + (x + 3y)$

. . . . . . $\displaystyle =\;(x+3y)(x + 2y) + (x+3y)$

. . . . . . $\displaystyle =\;(x+3y)(x + 2y+1)$

Quote:

$\displaystyle \text{Factor: }\; x^2 + (a + \tfrac{1}{a})xy + y^2$

$\displaystyle x^2 + (a + \tfrac{1}{a})xy + y^2$

. . $\displaystyle =\; x^2 + axy + \tfrac{1}{a}xy + y^2$

. . $\displaystyle =\;x(x + ay) + \tfrac{1}{a}y(x + ay)$

. . $\displaystyle =\;(x+ay)(x + \tfrac{1}{a}y)$
• Mar 29th 2012, 02:47 PM
Mhmh96
Re: Factor
Thank you very much,it is very clear now.