$\displaystyle h(t) = c - (d - 4t)^2$

At time $\displaystyle t = 0$, a ball was thrown upward from an initial height of 6 feet. Until the hall hit the ground, its height (in feet), after t seconds was given by function h above, in which $\displaystyle c $ and $\displaystyle d $ are positive constants. If the ball reached its maximum height of 106 ft at $\displaystyle t = 2.5 $, what what the height of the ball, in feet, at time $\displaystyle t = 1 $?

Obviously, this is a downward sloping parabola since it has a maximum.

So far, I've entered:

$\displaystyle 106(2.5) = c - (d - 4(2.5))^2$

but I'm not sure how to proceed from there