Have a couple more questions I'm struggling to understand for tomorrows test, if anyone can reply and explain to me how I reach my answer exactly or provide me a link where I can learn how to conquer the equation that would be greatly appreciated.
Consider the circle given X^2+Y^2=1. Determine the equation of the transformed function if the graph undergoes a horizontal stretch by a factor of 1/2, vertical stretch by a factor of 3, horizontal translation of 1 unit right and a vertical translation of 4 units down. (I essentially don't know where to start here)
Consider the conic section given by (x-2)^2 + (y+3)^2. Convert to general form and state the coordinates of the center and vertices.
AngleƟ has a terminal arm in the third quadrant. If cotƟ= 12, the values of the remaining five primary and reciprocal trig ratios.
Any help is greatly appreciate!
Thank you Emakarov, to clear it up and if this helps the first question 2 was suppose to be:
[U](x-2)^2/36 + [U](y+3)^2/16
for some reason it didn't allow the number to stay under the equation for the division.
Also Question 3 is: cotƟ=12/5
again the equation didn't have the 5 under it.
If this changes anything please let me know!
[QUOTE=Prentz;711136]the first question 2 was suppose to be:
[U](x-2)^2/36 + [U](y+3)^2/16[quote]My guess is this means . This is still not an equation, but corresponds to an ellipse with the center at (2, -3).
[QUOTE=emakarov;711139][QUOTE=Prentz;711136]the first question 2 was suppose to be:
[U](x-2)^2/36 + [U](y+3)^2/16The vertices of an ellipse are not the foci, they are the points on the ellipse where the curvature is maximum or minimum. They are the points at the ends of the axes. For an ellipse of the form they are at , , , and [tex]x_0- a, y_0)/tex].My guess is this means . This is still not an equation, but corresponds to an ellipse with the center at (2, -3).
By "vertices" do you mean foci (plural of "focus")? They are on the major axes at the distance from the center (a and b are semi-major axis and semi-minor axis, respectively).
This does not change the solution method.