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Math Help - application 2

  1. #1
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    application 2

    The number N of bacteria in a refrigerated food is given by:

    N(T)=25T^2-50T+300, 2(less then or equal to)T(less then or equal to)20

    Where T is the temperature of the foodin degrees celsius. When the food is removed from refrigeration, the temperature of the food is given by:

    T(t)=2t+1, 0(less then or equal to)t(less then or equal to)9

    Where t is the time in hours. Find the time when the bacteria count reaches 750.

    Ok so im thinking you use equation 2 and make it equal to 750 and then workout t. is it that simple or u need to defferintiate equation 1 and make it equal to equation 2s answear????? so confused, i know its probably easy its just that i havent done application questions in ages.

    Please help
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  2. #2
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    Crna Gora
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    Re: application 2

    Quote Originally Posted by iFuuZe View Post
    The number N of bacteria in a refrigerated food is given by:

    N(T)=25T^2-50T+300, 2(less then or equal to)T(less then or equal to)20

    Where T is the temperature of the foodin degrees celsius. When the food is removed from refrigeration, the temperature of the food is given by:

    T(t)=2t+1, 0(less then or equal to)t(less then or equal to)9

    Where t is the time in hours. Find the time when the bacteria count reaches 750.

    Ok so im thinking you use equation 2 and make it equal to 750 and then workout t. is it that simple or u need to defferintiate equation 1 and make it equal to equation 2s answear????? so confused, i know its probably easy its just that i havent done application questions in ages.

    Please help
    N(t)=25(2t+1)^2-50(2t+1)+300 \Rightarrow 750=25(2t+1)^2-50(2t+1)+300

     t \approx 2.18
    Thanks from iFuuZe
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  3. #3
    Junior Member
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    Oct 2010
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    Re: application 2

    Cheers buddy, youre a legend for doing this.
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