Given that delta (Δ) is an acute angle such that cos delta(Δ)= 1/4x find the expression for sin 2delta(Δ) in terms of x how to do such a question??????
Last edited by mathkid12; Mar 18th 2012 at 01:30 PM.
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Originally Posted by mathkid12 Given that delta (Δ) is an acute angle such that cos delta(Δ)= 1/4x find the expression for sin 2delta(Δ) in terms of x how to do such a question?????? $\displaystyle \cos(\Delta) = \frac{1}{4x}$ or $\displaystyle \frac{1}{4} x$ ???
second one, 1/4 x (sorry i cant type the equations properly i dont know how??)
Originally Posted by mathkid12 second one, 1/4 x (sorry i cant type the equations properly i dont know how??) Then $\displaystyle \sin(\Delta)=\sqrt{1-\frac{x^2}{16}}$ Learn some basic LaTeX. [TEX]\cos(\Delta)=\frac{x}{4}[/TEX] gives $\displaystyle \cos(\Delta)=\frac{x}{4}$.
thanks alot
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