# Thread: AS Mathematics Pure Core 2 - Sequences and Series Help!

1. ## AS Mathematics Pure Core 2 - Sequences and Series Help!

I need helping forming the equation given in the question, any help?

The sum of the first three terms of a geometric progression is 14. If the first term is 2, and the common ratio is r , show that r2 + r - 6 = 0

I tried substituting a = 2 and n = 3 into the geometric formula for the sum of a series, such that 2(r3 - 1) / (r - 1) = 14, but I can't get it to equal anything near the equation given in the question, so I think I'm doing something wrong...

2. ## Re: AS Mathematics Pure Core 2 - Sequences and Series Help!

Originally Posted by LarsaSolidor
I need helping forming the equation given in the question, any help?

The sum of the first three terms of a geometric progression is 14. If the first term is 2, and the common ratio is r , show that r2 + r - 6 = 0

I tried substituting a = 2 and n = 3 into the geometric formula for the sum of a series, such that 2(r3 - 1) / (r - 1) = 14, but I can't get it to equal anything near the equation given in the question, so I think I'm doing something wrong...
$\displaystyle 2+2r+2r^2=14$ solve for $\displaystyle r~.$