# rate time problem

• Mar 15th 2012, 02:53 PM
joshuaa
rate time problem
Tom can harvest the wheat in 20 minutes. Roza can harvest the wheat in 42 minutes. If they work together, how long does it take to harvest the wheat?

(Thinking)
• Mar 15th 2012, 03:03 PM
skeeter
re: rate time problem
tom's rate of job performance ... (1 job)/(20 min)

roza's rate of job performance ... (1 job)/(42 min)

rate together in jobs/min ... (1/20) + (1/42)

now use the relationship ...

(rate together)(time in minutes together) = 1 job completed

solve for (time in minutes together)
• Mar 15th 2012, 03:39 PM
joshuaa
Re: rate time problem
[(1/20) + (1/42)]t = 1
(2/420)t = 1
(1/210)t = 1
t = 210 minutes

i think that i made somethig wrong
• Mar 15th 2012, 04:06 PM
skeeter
Re: rate time problem
Quote:

Originally Posted by joshuaa
[(1/20) + (1/42)]t = 1
(2/420)t = 1
(1/210)t = 1
t = 210 minutes

i think that i made somethig wrong

$\displaystyle \frac{1}{20} + \frac{1}{42} = \frac{21}{420} + \frac{10}{420}$

try again
• Mar 15th 2012, 04:33 PM
joshuaa
Re: rate time problem
[(1/20) + (1/42)]t = 1
[(21/420) + (10/420)]t = 1
(31/420)t = 1
t = 420/31 = 13.55 minutes (Rounded to 2 d.p)

is the answer correct this time?
• Mar 15th 2012, 04:41 PM
skeeter
Re: rate time problem
Quote:

Originally Posted by joshuaa
[(1/20) + (1/42)]t = 1
[(21/420) + (10/420)]t = 1
(31/420)t = 1
t = 420/31 = 13.55 minutes (Rounded to 2 d.p)

is the answer correct this time?

does the solution make sense? what do you think?
• Mar 15th 2012, 05:26 PM
joshuaa
Re: rate time problem
it does not make sense. could you please explain more?
• Mar 15th 2012, 05:28 PM
skeeter
Re: rate time problem
Quote:

Originally Posted by joshuaa
it does not make sense. could you please explain more?

why do you think it does not make sense?
• Mar 15th 2012, 05:31 PM
joshuaa
Re: rate time problem
the time should be more than 20 minutes.
• Mar 15th 2012, 05:33 PM
skeeter
Re: rate time problem
Quote:

Originally Posted by joshuaa
the time should be more than 20 minutes.

come on Josh ... THINK!

if it took you 20 minutes to do a job by yourself, would it take more or less time if you had help?
• Mar 15th 2012, 05:36 PM
joshuaa
Re: rate time problem
lol it will take less if i got help from a faster lady, not 42 minutes
• Mar 15th 2012, 07:26 PM
Wilmer
Re: rate time problem
C'mon Josh...by yourself, it takes you 20 minutes to do the job; Ok?
So if you get ANY help whatsoever, including from slowest person around,
it will then take less than 20 minutes to do the job...see that?

Say it takes you 20 minutes to paint 20 doors.
If you get help from a slow painter who can paint only 1 door in 19 minutes,
then the job took 19 minutes, right? You only needed to paint 19...
• Mar 17th 2012, 11:47 AM
joshuaa
Re: rate time problem
You're absolutely right, Wilmer. This means that there are some situations in which I will not get help at all. Imagine that the slower painter can paint 1 door in 20 minutes! Then what will happen? No help, right? But, what will happen to the last door?
• Mar 17th 2012, 02:21 PM
Wilmer
Re: rate time problem
After you painted 19 doors, slowpoke will have painted 19/20 of the last door:
so both of you will work together to finish the 1/20 of door left.
In other words, if slowpoke is so slow he can only paint 1 square inch of a door
after 19 minutes, then quits, you still save a little time because you don't have
to paint that 1 square inch!

Art can do a job in 21 minutes. Ben can do the same job in 28 minutes.
If they work together, how long does it take to do the job?

Art, in 1 minute : 1/21 of job
Ben, in 1 minute: 1/28 of job
Art + Ben, in 1 minute : 1/21 + 1/28 = (28 + 21) / (21*28) = 49/588 = 1/12 of job
So they take 12 minutes if working together.

For a general case equation, let one worker's time = a and the other = b.
So in 1 minute, 1/a + 1/b of job gets done.
So working together = a*b / (a + b) minutes.
Let's see: 21 * 28 / (21 + 28) = 588 / 49 = 12