Problem:

$\displaystyle \frac{5x}{x-1}-3=\frac{2x+5}{x^2-1}$

Solution

$\displaystyle x=2$

$\displaystyle x=-\frac{1}{2}$

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- Mar 15th 2012, 11:56 AMvaironxxrdRational equation with two solutions
Problem:

$\displaystyle \frac{5x}{x-1}-3=\frac{2x+5}{x^2-1}$

Solution

$\displaystyle x=2$

$\displaystyle x=-\frac{1}{2}$ - Mar 15th 2012, 12:11 PMskeeterRe: Rational equation with two solutions
$\displaystyle \frac{5x}{x-1}-3=\frac{2x+5}{x^2-1}$

common denominator ...

$\displaystyle \frac{5x(x+1)}{(x-1)(x+1)}-\frac{3(x^2-1)}{x^2-1}=\frac{2x+5}{x^2-1}$

numerators form the equation ...

$\displaystyle 5x(x+1) - 3(x^2-1) = 2x+5 \, \, ; \, \, x \ne \pm 1$

take it from here? - Mar 15th 2012, 12:25 PMvaironxxrdRe: Rational equation with two solutions
- Mar 15th 2012, 12:28 PMskeeterRe: Rational equation with two solutions
typo

- Mar 15th 2012, 12:35 PMvaironxxrdRe: Rational equation with two solutions