Find the equation of the line CB

hello, this is my question:

The point A(3,2) is one end of the diameter AB of a circle. Both A and B lie on the line y=1/3x+1.

The point C(1,4) lies on the circumference of the circle.

Fine the equation of CB.

im not too sure at all how i would do this question so i would require some help please! could you write up step by step what i have to do and explain fully so i can try and understand what is going on?!

thanks!

Re: Find the equation of the line CB

Quote:

Originally Posted by

**andyboy179** .....could you write up step by step what i have to do and

explain fully so i can try and understand what is going on?!

That's your teacher's job.

Re: Find the equation of the line CB

Re: Find the equation of the line CB

Hi andyboy79,

The following may be of more help

1 the perpendicular bisector of AC passes thru the circle center

2 solution of y=1/3x+1 and ! above gives the center

3 radius of circle = distance between A and center

4 determine point B using radius and y=1/3x+1

5 CB has same slope as 1.Use point slope formular to get equation of CBl