Well, me and my son have been trying to solve a seemingly simple question but we just can not figure out the answer and how that answer is achieved:
Tony has one liter juice mixed with a proportion of 1:3
Robert also has one liter juice mixed with a proportion of 1:4
The two (Tony and Robert) mix their juices together in one jug.
1. What is the proportion of the mixed juice (Tony and Robert's)?
2. How much water (in deciliters) should be added so that Tony and Robert's mix again assumes the proportion of 1:4?
I hope some mathematician would be kind enough to help us on this. My son is kind of disappointed that we have not been able to figure out the answers and how to achieve them.
skeeter, thanks for taking your time. That's what me and my son originally figured out but the answer from the school book is different. According to the book the ratio will be 4.5 parts juice, 15.5 parts water (or rather 1 : 3.45 ratio). That's where we kind of got totally confused.
Also the answer to question 2 turns out to be 2.5 deciliters water that must be added!
Of course even if we try to simplify the 2 part juice, 7 parts water to 1 part juice, 3.5 parts water it does not make us wiser.
How the 4.5 parts to 15.5 part ratio answer to question 1 is still something of an enigma to us!
tony; 0.25 L of juice, 0.75 L of water
robert; 0.20 L of juice, 0.80 L of water
mix; 0.45 L of juice , 1.55 L of water ( which gives your 4.5 : 15.5 ratio)
want new mix to be 1:4 ...
0.45 L juice , 4(0.45 L) water or 0.45 L juice , 1.80 L water ... so .25 L need to be added to 1.55 L of water to yield the 1.80 L