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Math Help - Log question

  1. #1
    Newbie
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    Mar 2012
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    Timbuktu
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    Log question

    Im pretty sure im meant to be solving this as a logarithim.
    Question is:

    Find all real solutions if any of:

    3^x multiply 27^(2-x) = 9

    Very confused...

    Thanks.

    PS pleaqse include working so i can study it when youre done.
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  2. #2
    Senior Member
    Joined
    Nov 2011
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    Crna Gora
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    Re: Log question

    Quote Originally Posted by Hooperoo View Post
    Im pretty sure im meant to be solving this as a logarithim.
    Question is:

    Find all real solutions if any of:

    3^x multiply 27^(2-x) = 9

    Very confused...

    Thanks.

    PS pleaqse include working so i can study it when youre done.
     3^x \cdot 27^{2-x}=9

    3^x \cdot 3^{6-3x}=3^2

    3^{6-2x}=3^2

    6-2x=2

    x=2
    Thanks from Hooperoo
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  3. #3
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    Joined
    Mar 2012
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    San Leandro
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    Re: Log question

    I use to love problems like this because it would be like one of those hidden things... The first thing that would come into my mind is how are all these numbers kinda related so 3, 9 and 27. All multiples of 3 right... and if we are dealing with exponents then you kind of got to say, "Ok, well... 9 = 3 to the what (3^?)... oh (3^2) = 9" and so on.

    Just a quick tip if anyone else is reading
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