I have the following function

$\displaystyle y = \frac{2x^2-7x-4}{x+5}$

X intercepts =

$\displaystyle 0 = 2x^2-7x-4$

$\displaystyle (x-4)(2x+1)$

x intercepts are 4, and $\displaystyle -\frac{1}{2}$

Vertical asymptotes =

$\displaystyle 0 = x+5$

$\displaystyle x = -5$

Vertical asymptote is were x= -5

Is this correct?