Results 1 to 15 of 15

Math Help - Exponents

  1. #1
    Senior Member
    Joined
    Jul 2007
    Posts
    290

    Exponents

    We've been on exponents for a little while now in class and I keep getting confused . Bear with me please.


    I'm to simplify

    (3x(sqrt(x^3))^2

    From here I

    (3^2)(x^2)(x^3)

    9x^5


    Next one is

    x^e(x^e)^2

    (x^e)(x^2e)

    x^(2e + e)

    Please let me know if I did those correctly =)
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie
    Joined
    Sep 2007
    Posts
    20
    Quote Originally Posted by JonathanEyoon View Post
    We've been on exponents for a little while now in class and I keep getting confused . Bear with me please.


    I'm to simplify

    (3x(sqrt(x^3))^2

    From here I

    (3^2)(x^2)(x^3)

    9x^5


    Next one is

    x^e(x^e)^2

    (x^e)(x^2e)

    x^(2e + e)

    Please let me know if I did those correctly =)
    both are correct. why don't you write x^(3e) for the second one
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Senior Member
    Joined
    Jul 2007
    Posts
    290
    Quote Originally Posted by mahurshi View Post
    both are correct. why don't you write x^(3e) for the second one


    You know I thought about doing that but I thought it was wrong
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Senior Member
    Joined
    Jul 2007
    Posts
    290
    For the next two, it's not part of our graded homework assignment but I'd still like to know how to do them if you guys don't mind .


    ((y^-2)(e^y))^2


    (y^-4)(e^2y)

    e^(2y) / y^4 <------------- Did I do that correctly ?


    Next one is:

    4x^(3pi + 1) / x^2

    4^(3pi + 1) / x


    From here I multipled 3pi + 1 = 10.4247796.

    So would the final answer be 10.4247796 / x ?
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    9,855
    Thanks
    321
    Awards
    1
    Quote Originally Posted by JonathanEyoon View Post
    For the next two, it's not part of our graded homework assignment but I'd still like to know how to do them if you guys don't mind .


    ((y^-2)(e^y))^2


    (y^-4)(e^2y)

    e^(2y) / y^4 <------------- Did I do that correctly ?


    Next one is:

    4x^(3pi + 1) / x^2

    4^(3pi + 1) / x


    From here I multipled 3pi + 1 = 10.4247796.

    So would the final answer be 10.4247796 / x ?
    The first one is correct, the second one has a problem.

    \frac{4x^{3 \pi + 1}}{x} = 4x^{3 \pi + 1} \cdot x^{-1} = 4x^{3 \pi + 1 - 1} = 4x^{3 \pi}

    -Dan
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Senior Member
    Joined
    Jul 2007
    Posts
    290
    For the second problem i'm a little confused. I just noticed that I canceled out an X in the beginning when they have different exponents. Was I able to do that?


    The original problem is

    4x^(3pi + 1) / x^2


    I originally factored out an X since it is both in the numerator and denominator. I was able to do that right?

    Well from your explanation, you still had an X in the numerator when I factored it out. mmmMMmm... i'm lost can you walk me through it Sorry to be such a pain
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Senior Member
    Joined
    Jul 2007
    Posts
    290
    oh and I was also wondering about this problem



    (a^(n+1))(3^(n+1)) / (a^n)(3^n)
    Follow Math Help Forum on Facebook and Google+

  8. #8
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by JonathanEyoon View Post
    oh and I was also wondering about this problem



    (a^(n+1))(3^(n+1)) / (a^n)(3^n)
    \frac {a^{n + 1} \cdot 3^{n + 1}}{a^n \cdot 3^n} = \frac {(3a)^{n + 1}}{(3a)^n}

    the rest is trivial....whoa!, look at me, using the word "trivial." spoken like a true mathematician
    Follow Math Help Forum on Facebook and Google+

  9. #9
    Senior Member
    Joined
    Jul 2007
    Posts
    290
    Quote Originally Posted by Jhevon View Post
    \frac {a^{n + 1} \cdot 3^{n + 1}}{a^n \cdot 3^n} = \frac {(3a)^{n + 1}}{(3a)^n}

    the rest is trivial....whoa!, look at me, using the word "trivial." spoken like a true mathematician

    Hey Jhevon!

    Ok from (3a)^ (n+1) / (3a)^n

    I would cancel the (3a) out from both top and bottom leaving me with

    (N+1) / N

    N would cancel out which would result in the simplified form of 1 right?


    Also can you help me out about my inquiries on post #6 i'm so confused with that problem. I'm trying to understand it.
    Follow Math Help Forum on Facebook and Google+

  10. #10
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by JonathanEyoon View Post
    Hey Jhevon!

    Ok from (3a)^ (n+1) / (3a)^n

    I would cancel the (3a) out from both top and bottom leaving me with

    (N+1) / N

    N would cancel out which would result in the simplified form of 1 right?
    what?!!! how can you cancel bases and leave powers? that makes no sense. i guess it wasn't trivial after all.

    use the fact that \frac {x^a}{x^b} = x^{a - b}


    Also can you help me out about my inquiries on post #6 i'm so confused with that problem. I'm trying to understand it.
    lemme check ....use the same rule above for that question
    Follow Math Help Forum on Facebook and Google+

  11. #11
    Senior Member
    Joined
    Jul 2007
    Posts
    290
    (3a)^(n+1) / (3a)^n


    so then the N will subtract out leaving

    (3a) / (3a) which is 1?


    *sigh* I forgot the rules and stuff for exponents since it's been a little while. =/
    Follow Math Help Forum on Facebook and Google+

  12. #12
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by JonathanEyoon View Post
    (3a)^(n+1) / (3a)^n


    so then the N will subtract out leaving

    (3a) / (3a) which is 1?
    no. you would get 1 if you divided something by itself. that is not the case here. (3a)^{n + 1} is not the same as (3a)^n

    *sigh* I forgot the rules and stuff for exponents since it's been a little while. =/
    i just told you the rule you should use, you don't need to remember anything.

    \frac {x^a}{x^b} = x^{a - b}

    here, your x is 3a, your a is n + 1 and your b is n. just plug into the formula
    Follow Math Help Forum on Facebook and Google+

  13. #13
    Senior Member
    Joined
    Jul 2007
    Posts
    290
    So then it'll be (3a)^(n+1-n)


    Final answer is 3a?


    For the other one,


    4x^(3pi + 1) / x^2


    If using the formula it would be

    4x^(3pi + 1 - 2)

    which would be 4x^(3pi - 1)

    Did I do that right?
    Follow Math Help Forum on Facebook and Google+

  14. #14
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by JonathanEyoon View Post
    So then it'll be (3a)^(n+1-n)


    Final answer is 3a?


    For the other one,


    4x^(3pi + 1) / x^2


    If using the formula it would be

    4x^(3pi + 1 - 2)

    which would be 4x^(3pi - 1)

    Did I do that right?
    yes!
    Follow Math Help Forum on Facebook and Google+

  15. #15
    Senior Member
    Joined
    Jul 2007
    Posts
    290
    Thanks alot!!! I'm gonna do some research to online to see if i can get a more in depth look at exponents. I need to review!! Thanks again!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Exponents and Log Help!!
    Posted in the Algebra Forum
    Replies: 17
    Last Post: August 14th 2011, 10:21 AM
  2. Exponents
    Posted in the Algebra Forum
    Replies: 8
    Last Post: April 24th 2010, 04:30 PM
  3. exponents
    Posted in the Algebra Forum
    Replies: 2
    Last Post: April 17th 2010, 08:37 AM
  4. Exponents
    Posted in the Algebra Forum
    Replies: 2
    Last Post: August 18th 2008, 09:51 PM
  5. exponents
    Posted in the Algebra Forum
    Replies: 2
    Last Post: April 28th 2008, 01:53 PM

Search Tags


/mathhelpforum @mathhelpforum