Results 1 to 7 of 7

Math Help - function help

  1. #1
    Newbie
    Joined
    Mar 2012
    From
    Canada
    Posts
    4

    function help

    I am really bad at this and need help to simplify the following:

    (1/2x+8)-(3x/(x+4)^2)+(1/2)
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,234
    Thanks
    27

    Re: function help

    Use BODMAS, expand the brackets first.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Mar 2012
    From
    Canada
    Posts
    4

    Re: function help

    It's starting to come back (I haven't taken math in years and I'm taking a course to upgrade right now), but I am a visual learner so what would help me the most is to actually see the steps then I get a better idea
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor
    Joined
    Dec 2007
    From
    Ottawa, Canada
    Posts
    3,069
    Thanks
    65

    Re: function help

    Quote Originally Posted by Halderz View Post
    (1/2x+8)-(3x/(x+4)^2)+(1/2)
    Hmmm...it's a bit "messy"; are you sure you wrote it down correctly?
    Could the (1/2x+8) be 1/(2x+8) instead?
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Newbie
    Joined
    Mar 2012
    From
    Canada
    Posts
    4

    Re: function help

    You're right, it is. My mistake.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    MHF Contributor
    Joined
    Dec 2007
    From
    Ottawa, Canada
    Posts
    3,069
    Thanks
    65

    Re: function help

    So, is this the exact way the problem is:
    Code:
       1         3x      1
    ~~~~~~ - ~~~~~~~~~ + ~
    2x + 8   (x + 4)^2   2
    If so, then above then can be re-written this way:
    Code:
        1            3x         1
    ~~~~~~~~ - ~~~~~~~~~~~~~~ + ~
    2(x + 4)   (x + 4)(x + 4)   2
    Do you follow that?

    I suggest you google "simplifying" as next step: you'll get plenty of helpful sites
    with the process fully explained; come back if you have more questions.
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Newbie
    Joined
    Mar 2012
    From
    Canada
    Posts
    4

    Re: function help

    Thanks. That helped.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 20
    Last Post: November 27th 2012, 05:28 AM
  2. Replies: 2
    Last Post: April 17th 2012, 10:50 AM
  3. Replies: 0
    Last Post: October 19th 2011, 04:49 AM
  4. Replies: 4
    Last Post: October 27th 2010, 05:41 AM
  5. Replies: 3
    Last Post: September 14th 2010, 02:46 PM

Search Tags


/mathhelpforum @mathhelpforum