algebraic fraction question

hi

can anyone clear my mind

Q. 1/3x -2/x+3

I understand tha I have to make both denominators the same and to do this I multiply them together.

I make the answer to be 3x^2+3 and would use this as the denominator, but the answer in my book tells me that the denomonator should be 3(x+3)

am I missing something?

Dave

Re: algebraic fraction question

$\displaystyle \frac{1}{3} \cdot x -\frac{2}{x+3}=\frac {x(x+3)-6}{3(x+3)}$

Re: algebraic fraction question

Re: algebraic fraction question

Quote:

Originally Posted by

**davellew69** why do I write 3(x+3)

$\displaystyle \frac{a}{b}+\frac{c}{d}=\frac{a \cdot d+b \cdot c}{b \cdot d} $

Re: algebraic fraction question

Quote:

Originally Posted by

**davellew69** 1/3x -2/x+3

Brackets required: x/3 - 2(x+3)