(100 / 4 root x) - (36 /x^2) I get this far: (10^2 / x^(1/2)) - (6^2 /x^2) EDIT: Anyone have any idea?
Last edited by Jeavus; September 26th 2007 at 02:43 PM.
Follow Math Help Forum on Facebook and Google+
Originally Posted by Jeavus (100 / 4 root x) - (36 /x^2) I get this far: (10^2 / x^(1/2)) - (6^2 /x^2) (You missed a 4 in the first fraction, by the way.) You have two options as I see it. 1. Add the fractions. Find a common denominator. The LCM of is . So 2. Simplify each term independently. Now factor: -Dan
I think you misinterpreted the question. 4 root x It looks like this: http://img255.imageshack.us/img255/8985/4rootuh6.png
Originally Posted by Jeavus I think you misinterpreted the question. 4 root x It looks like this: http://img255.imageshack.us/img255/8985/4rootuh6.png Ahhhhhh.... Hmmmm.... It doesn't seem like we'd want to add the fractions here, so I would simplify the first term, then factor: -Dan
I suppose you could also treat this as the difference between two squares: -Dan
How does it become 10 / x^1/8?
Originally Posted by Jeavus How does it become 10 / x^1/8? Recall that . So your question becomes: How do you take the square root of ? I assume you can do the square root of 100, so how do you do the square root of ? Thus -Dan
View Tag Cloud