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One side of an isoceles right triangle is x + 2 and its hypotenuse is x +3. Find the perimeter and the area. p = 2l * 2w
How exactly could I solve this?
I would say:
(x+3)^2 = (x+2)^2 * h is this right just for a start?
If so does it mean (x+3)-(x+2) = b?
I believe the above idea is disappointing to you guys.
hypotenuse = SQRT[(x + 2)^2 + (x + 2)^2] : NOT x + 3
What you have is a right triangle with one leg = x + 2 and the hypotenuse = x + 3; so other leg
= SQRT[(x + 3)^2 - (x + 2)^2]
= SQRT(2x + 5)
So triangle has sides SQRT(2x + 5), x +2 and x + 3
Please use google to find out about perimeter and area of a right triangle.
You assumed: p = 2l * 2w
That's perimeter of a rectangle!
You are quite unaware of the basics. Are you attending math classes?