# Write the expression as a sum, difference, or product of logarithms

• Mar 4th 2012, 04:04 PM
aikenfan
Write the expression as a sum, difference, or product of logarithms
Attachment 23309

I am in need of help please...I have no idea where to begin on this one...could somebody take me through the process please?
• Mar 4th 2012, 04:50 PM
bjhopper
Re: Write the expression as a sum, difference, or product of logarithms
log baseb (4x^9/z^8)^1/2 = logb 2x^3/z^4 = log 2 +3logx -4logz (all logs base b)
• Mar 5th 2012, 12:26 AM
princeps
Re: Write the expression as a sum, difference, or product of logarithms
Quote:

Originally Posted by aikenfan
Attachment 23309

I am in need of help please...I have no idea where to begin on this one...could somebody take me through the process please?

$\log_{b}\sqrt {\frac{4x^9}{z^8}}=\frac{1}{2} \cdot \log_{b} \frac{4x^9}{z^8}=\frac{1}{2} \cdot(\log_{b}4x^9-\log_{b}z^8)=$

$=\frac{1}{2} \cdot (\log_{b} 4+9\log_{b} x-8 \log_{b}z)$
• Mar 5th 2012, 05:37 AM
bjhopper
Re: Write the expression as a sum, difference, or product of logarithms
[QUOTE=princeps;708543] $\log_{b}\sqrt {\frac{4x^9}{z^8}}=\frac{1}{2} \cdot \log_{b} \frac{4x^9}{z^8}=\frac{1}{2} \cdot(\log_{b}4x^9-\log_{b}z^8)=$

$=\frac{1}{2} \cdot (\log_{b} 4+9\log_{b} x-8 \log_{b}z)$[/QUOTE

Thanks for correcting my mistake