It doesn't seem especially tough but there's not an example in the book and it was on a quiz today. Please note that I did consult the Inequality sticky at the top of the forum but I didn't see one quite like this. I apologize in advance if I missed it.
My first thought was to multiply everything by the denominator 3 so that:
Then: add 3 to 6 so that:
Then: divide by 3 so that:
Then: add 1 to both sides so that:
So that...
x is equal to +2 and x is equal to -2
It seemed tidy enough at the time but I have a feeling it's wrong; that maybe I should multiplied 2x-1 by 3 at some point or that I'm remiss in some way or another. Any and all help is appreciated. Thanks.
A Picard facepalm moment for me... I've also noticed that not multiplying -1 or 2 that my answer still comes out to same. Will that stand up for precisely similar problems?
But what of something like
A.
would I then have to go with the LCD of 12 and then have...
Again, thank you so much.
Or does that 3 just get left alone, so that:
And (sorry), would I then divide the right side by the 9 or 3 (depending on which is correct--if correct at all).