Complex Conjugate Roots and the Quadratic Formula

Hello, there.

I have the quadratic equation http://www.mathhelpforum.com/math-he...s1_q20_g01.gifhttp://www.mathhelpforum.com/math-he...s1_q20_g01.gif

Using , I get .

Now, I know the answer to this question is two complex conjugate roots, , my question is how? The square root of 24 isn't 6. I'm confused.

I guess I'm just asking for the steps to get there.

Thank you in advance.

Re: Complex Conjugate Roots and the Quadratic Formula

sqrt(-1)=i

and

sqrt(24)=2sqrt(6)

so sqrt(-24)=i2sqrt(6)

now you try.

Re: Complex Conjugate Roots and the Quadratic Formula

I'm still not sure I see where the comes from..

This is on the tip of my tongue from when I took Algebra, but I'm not sure I remember how to factor radicals.

Edit: Nevermind I get it. so