$k^2-7=0$
I don't even know where to start. There wasn't any examples in my book that matches this problem. If anyone could assist.

Edit: I'm sorry, It's "0"

you can start from this point:

$k^2=7$

solve for k ...

OR

from this piont:

$k^2-(\sqrt 7)^2=0$

factorize and solve ...

Originally Posted by HellBunny
$k^2-7=0$
I don't even know where to start. There wasn't any examples in my book that matches this problem. If anyone could assist.

Edit: I'm sorry, It's "0"
What do you know about the difference of two squares?

Originally Posted by e^(i*pi)
What do you know about the difference of two squares?
One is easier to solve than the other
But now I understand how to solve the problem. I should had seen it in the beginning. Thanks you two.

Incorrect. Why did you draw that conclusion? Study posts #2 and #3 carefully.

That's the wrong answer? Then I don't know. Just thought it was right. What you guys want me to answer? 7 Couldn't be squared, so I assumed k={7,-7} OH! I see. I written down the answer incorrectly.
$+ - \sqrt 7$

There you go.