• Jan 15th 2012, 02:19 PM
HellBunny
$\displaystyle k^2-7=0$
I don't even know where to start. There wasn't any examples in my book that matches this problem. If anyone could assist.

Edit: I'm sorry, It's "0"
• Jan 15th 2012, 02:42 PM
razemsoft21
you can start from this point:

$\displaystyle k^2=7$

solve for k ...

OR

from this piont:

$\displaystyle k^2-(\sqrt 7)^2=0$

factorize and solve ...
• Jan 15th 2012, 02:48 PM
e^(i*pi)
Quote:

Originally Posted by HellBunny
$\displaystyle k^2-7=0$
I don't even know where to start. There wasn't any examples in my book that matches this problem. If anyone could assist.

Edit: I'm sorry, It's "0"

What do you know about the difference of two squares?
• Jan 15th 2012, 04:01 PM
HellBunny
Quote:

Originally Posted by e^(i*pi)
What do you know about the difference of two squares?

One is easier to solve than the other(Shake)(Evilgrin)
But now I understand how to solve the problem. I should had seen it in the beginning. Thanks you two.
$\displaystyle + - \sqrt 7$ (Clapping)