• Jan 15th 2012, 02:19 PM
HellBunny
$k^2-7=0$
I don't even know where to start. There wasn't any examples in my book that matches this problem. If anyone could assist.

Edit: I'm sorry, It's "0"
• Jan 15th 2012, 02:42 PM
razemsoft21
you can start from this point:

$k^2=7$

solve for k ...

OR

from this piont:

$k^2-(\sqrt 7)^2=0$

factorize and solve ...
• Jan 15th 2012, 02:48 PM
e^(i*pi)
Quote:

Originally Posted by HellBunny
$k^2-7=0$
I don't even know where to start. There wasn't any examples in my book that matches this problem. If anyone could assist.

Edit: I'm sorry, It's "0"

What do you know about the difference of two squares?
• Jan 15th 2012, 04:01 PM
HellBunny
Quote:

Originally Posted by e^(i*pi)
What do you know about the difference of two squares?

One is easier to solve than the other(Shake)(Evilgrin)
But now I understand how to solve the problem. I should had seen it in the beginning. Thanks you two.
• Jan 15th 2012, 04:07 PM
Quacky
Incorrect. Why did you draw that conclusion? Study posts #2 and #3 carefully.
• Jan 15th 2012, 05:57 PM
HellBunny
That's the wrong answer? Then I don't know. Just thought it was right. What you guys want me to answer? 7 Couldn't be squared, so I assumed k={7,-7} OH! I see. I written down the answer incorrectly.
$+ - \sqrt 7$ (Clapping)
• Jan 15th 2012, 06:08 PM
Quacky