1. ## Algebraic fractions

$\frac{x+3}{x}-\frac{2}{x-2}=0$

Will somebody please explain how I can get a minus sign between the first fraction and the second so that I can put the minus sign between the division lines of the first and second fractions please?

Thanks

David

Thank you Quacky for that useful information

Now for the next part.

$\(x-2)(x+3)\div(x)(x-2)}$ $-\(2x)\div(x^2 -2)=0$

It does not seem to be formatting as previously, I need more help and experience as I must be doing something incorrect?

I will have to come back to this later?

2. ## Re: Algebraic fractions

You have written $$\frac{x+3}{x}$$$$\frac{2}{x-2}$$

You shouldn't tag each individual fraction. Tag the whole equation, as below, and then you can simply slot in the minus sign:

[TEX]\frac{x+3}{x}-\frac{2}{x-2}=0[/TEX] gives:

$\frac{x+3}{x}-\frac{2}{x-2}=0$

3. ## Re: Algebraic fractions

Originally Posted by David Green
Now for the next part.

$\(x-2)(x+3)\div(x)(x-2)}$ $-\(2x)\div(x^2 -2)=0$

It does not seem to be formatting as previously, I need more help and experience as I must be doing something incorrect?

I will have to come back to this later?
The code:

[TEX]\frac{(x+2)(x+3)}{(x)(x-2)}-\frac{2x}{x^2-2}=0[/TEX] gives:

$\frac{(x+2)(x+3)}{(x)(x-2)}-\frac{2x}{x^2-2}=0$

4. ## Re: Algebraic fractions

$\frac{(x-2)(x+3)}{(x)(x-2)}-\frac{(2x)}{(x)(x-2)}=0$

$\frac{(x^2+3x-2x-6)}{(x^2-2x)}-\frac{(2x)}{(x^2-2x)} =$

$\(x^2+x-6)}-{(2x)}=x+6$

Somewhere here I am making a mistake in the maths but at present I can't see it, and although I am brand new to latex, it's not the latex that is incorrect it is my maths

The answer does not seem correct to me?

Any help greatly appreciated to point out my mistake

David

5. ## Re: Algebraic fractions

Originally Posted by David Green
$\frac{(x-2)(x+3)}{(x)(x-2)}-\frac{(2x)}{(x)(x-2)}=0$

$\frac{(x^2+3x-2x-6)}{(x^2-2x)}-\frac{(2x)}{(x^2-2x)} =$

$\(x^2+x-6)}-{(2x)}=x+6$

Somewhere here I am making a mistake in the maths but at present I can't see it, and although I am brand new to latex, it's not the latex that is incorrect it is my maths

The answer does not seem correct to me?

Any help greatly appreciated to point out my mistake

David
$\frac{(x^2+3x-2x-6)}{(x^2-2x)}-\frac{(2x)}{(x^2-2x)} =0$
$\frac{(x^2+x-6)}{(x^2-2x)}-\frac{(2x)}{(x^2-2x)} =0$
$\frac{(x^2+x-6-2x)}{(x^2-2x)}=0$
$x^2-x-6=0$