$\displaystyle [(2x^1^/^3)-(5^1^/^3)]^3 = 35$
find X ???
sorry but this is not the right solution in my book....
here is the main problem :
$\displaystyle (2x^1^/^3 - 5^1^/^3) (4x^2^/^3 + 2(5x)^1^/^3 + 25^1^/^3) = 35$
then i tried to simplify it as i wrote in the 1st post
the solution set is {5}
Always state the problem in full, we can only answer what's put in front of us
Start by expanding the brackets:here is the main problem :
$\displaystyle (2x^1^/^3 - 5^1^/^3) (4x^2^/^3 + 2(5x)^1^/^3 + 25^1^/^3) = 35$
then i tried to simplify it as i wrote in the 1st post
the solution set is {5}
Multiplying $\displaystyle 2x^{1/3}$ by each term in the second bracket:
$\displaystyle 8x + 4\sqrt[3]{5}x^{2/3} + 2\sqrt[3]{25}x^{1/3}$
Multiplying $\displaystyle -5^{1/3}$ by each term in the second bracket
$\displaystyle -4\sqrt[3]{5}x^{2/3} - 2\sqrt[3]{25}x^{1/3} - 5$
The expanded form is the sum of these:
$\displaystyle \left(8x + 4\sqrt[3]{5}x^{2/3} + 2\sqrt[3]{25}x^{1/3}\right)$
$\displaystyle + \left(-4\sqrt[3]{5}x^{2/3} - 2\sqrt[3]{25}x^{1/3} - 5\right) = 35$
Can you go from there? I expect a few terms will cancel