Hi, can anyone help me to prove this: If the roots of the equation $\displaystyle x^3-Lx^2+mx+n=0$ are the cosine of the angles of a triangle show that: $\displaystyle L^2=2m+2n+1$
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Well, you have three angles. Use them and see what happens. $\displaystyle \alpha$, $\displaystyle \beta$, $\displaystyle \pi - \alpha-\beta$ You have a Law of Cosines. Show us what you get.
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