Is there anyway of simplifying the following, if so could someone please show me how?
[(-2F)^2+((2F)^(1/2)*sin(pi/4)+(2F)^(1/2)*sin(pi/4))^2]^(1/2)
It is hard to follow your groupings.
But $\displaystyle ( - 2F)^2 = 4F^2 $ and $\displaystyle \sqrt {2F} \sin \left( {\frac{\pi }{4}} \right) = \sqrt F $.