hi, i nned to know how to answer this question: Find a set of values of x for the equation have two district roots, x^2-6x+k=0 im not too sure how i would complete this question, so could someone provide some help please? thanks!
Follow Math Help Forum on Facebook and Google+
Originally Posted by andyboy179 hi, i nned to know how to answer this question: Find a set of values of x for the equation have two district roots, x^2-6x+k=0 im not too sure how i would complete this question, so could someone provide some help please? thanks! If it has two distinct roots then the discriminant must be greater than 0: Where a=1, b=-6, c=k
-6^2-4x1x4>0 -36+-16>0 -52>0?
Originally Posted by andyboy179 -6^2-4x1x4>0 -36+-16>0 -52>0? a = 1 , b = -6 , c = k order of operations? try again ...
oh poo! -6^2-4x1xk>0 -36+-4k>0 >36+4k 36/4= 9 K=9?
Originally Posted by andyboy179 oh poo! -6^2-4x1xk>0 -36+-4k>0 >36+4k 36/4= 9 K=9? no ... 1. apparently, you do not understand the difference between and . 2. ? 3. you are solving an inequality ... where did the equal sign come from?
-6^2-4x1xk>0 36+-4k>0 36>4k 36/4= 9 k>9?
Originally Posted by andyboy179 -6^2-4x1xk>0 36+-4k>0 36>4k 36/4= 9 k>9? You changed the direction of the inequality in the last line but there is no need to since you were dividing by +4.
so what would be the set of values for x?
Originally Posted by andyboy179 so what would be the set of values for x? That's a good question, are you sure the question doesn't ask for the values of k instead of x? When we work out the nature of the roots (whether they're real/distinct) it's the coefficients of x that matter rather than values of x itself
it is definetly x! umm im not too sure how to do the next part then.
View Tag Cloud