hi,
i nned to know how to answer this question:
Find a set of values of x for the equation have two district roots, x^2-6x+k=0
im not too sure how i would complete this question, so could someone provide some help please?
thanks!
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hi,
i nned to know how to answer this question:
Find a set of values of x for the equation have two district roots, x^2-6x+k=0
im not too sure how i would complete this question, so could someone provide some help please?
thanks!
If it has two distinct roots then the discriminant must be greater than 0:Quote:
Originally Posted by andyboy179
Where a=1, b=-6, c=k
-6^2-4x1x4>0
-36+-16>0
-52>0?
a = 1 , b = -6 , c = kQuote:
Originally Posted by andyboy179
order of operations? try again ...
oh poo!
-6^2-4x1xk>0
-36+-4k>0
>36+4k
36/4= 9
K=9?
no ...Quote:
Originally Posted by andyboy179
1. apparently, you do not understand the difference betweenand
.
2.?
3. you are solving an inequality ... where did the equal sign come from?
-6^2-4x1xk>0
36+-4k>0
36>4k
36/4= 9
k>9?
You changed the direction of the inequality in the last line but there is no need to since you were dividing by +4.Quote:
Originally Posted by andyboy179
so what would be the set of values for x?
That's a good question, are you sure the question doesn't ask for the values of k instead of x?Quote:
Originally Posted by andyboy179
When we work out the nature of the roots (whether they're real/distinct) it's the coefficients of x that matter rather than values of x itself
it is definetly x! umm im not too sure how to do the next part then.