I would let x be the length of the shorter leg, then x + 2 is the length of the longer leg. By Pythagoras we then have:
Now collect like terms, simplify, and factor to find x.
Then the perimeter P will be:
Can someone please tell me if I managed to do this correctly?
"The length of one leg of a right triangle is 2 ft longer than the other leg. If the hypotenuse is 10 ft, find the perimeter of the triangle."
My answer was
P (perimeter) = 12+2y
If this is wrong someone please tell me. I don't understand how to do these types of problems at all.
Let the length of one side be 'x'. We now have a triangle such that we have
one side has length 'x'
the other side is 'x+2'
and the hypotenuse is '10'
so your perimeter = 10+(x+2)+x which simplifies too 12+2x
Now in order to solve that you need to use r^2= a^2+b^2
r = 10
a = x+2
b = x
Solve for x and plug into the perimeter equation and you will have an answer
I agree with MarkFL2.
e^(i*pi), i think you solved using a rectangle instead of a triangle :P
Also how do i use math symbols n stuff like you guys did? :S
Since I have X on the shorter leg, X+2 on the longer leg, and 10ft as the hypotenuse, shouldn't I just group common variables and get
P= 2x+12 OR P= 2(x+6) as my answer?