# Thread: Solving quadratic equations

1. ## Solving quadratic equations

I was solving this problem and ended up with 1.025^n=0.71+0.05n
I tried solving this equation for like 15 minutes with no use... can you please tell me how to solve it?

Thanks

2. ## Re: Solving quadratic equations

here see wolfarm

3. ## Re: Solving quadratic equations

Originally Posted by IBstudent
I was solving this problem and ended up with 1.025^n=0.71+0.05n
I tried solving this equation for like 15 minutes with no use... can you please tell me how to solve it?

Thanks

15 min. is nothing! What is the original problem?

1.025&#94;n&#61;0.71&#43;0.05n - Wolfram|Alpha

4. ## Re: Solving quadratic equations

The question is complicated, I am sure that you start with 1200000(1.025)^n/(1420+100n)=600

Can you please show me how to work this out?

Thanks in advance

5. ## Re: Solving quadratic equations

Originally Posted by IBstudent
The question is complicated, I am sure that you start with 1200000(1.025)^n/(1420+100n)=600

Can you please show me how to work this out?

Thanks in advance
First off, your post title is misleading. This equation is exponential, not quadratic.

Note that elementary algebraic methods will not work in finding a solution by hand.

I advise the use of technology to solve the equation. Another poster has provided you a link to that end.

6. ## Re: Solving quadratic equations

May I ask why you title this "Solving quadratic equations"? This is certainly not a quadratic equation. It is not even a polynomial equation.

The point the others are making is that there is no simple formula that will give you an exact answer. Probably the simplest thing to do is to graph y= 1.025^n and y= 0.71+ .05n on some kind of calculator or computer graphics system and "zoom" in on a point where they intersect.

You could also use some kind of numerical method such as Newton's method to find a numerical problem.